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Admin Panel testing

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Laxos2001

Hello i know php and can check if your admin panel contain backdoors for the lowest price if you are intersted contact me in chat

$10 AUD dalam 0 hari
(1 Ulasan)
0.0

9 freelancer menawar dengan rata-rata $23 untuk pekerjaan ini

grigorywazin

Hi, sir. I understood what you wanted. So... someone developer developed the admin panel and he/she can hide the "delete" function in source code so that you want to know it? No problem. All i want is "which Lebih banyak

$25 AUD dalam 1 hari
(34 Ulasan)
6.5
Grawlixsoft

Hello sir/madam, I am having 10 years of exprience in web development.I can deliver your project very quikly. Please contact to discuss further.

$30 AUD dalam 5 hari
(28 Ulasan)
5.9
palsoftsol

Dear Sir/Madam, I am certified penetration tester and security researcher. I am currently securing lot many websites and preventing them from being hacked and data breeches. I assure you to make your site 99.9999% sec Lebih banyak

$25 AUD dalam 1 hari
(17 Ulasan)
4.7
Letusstart2010

Dear Employer, I read the job details and absolutely sure that I can do the job very well. I've proven skills in PHP, MYSQL, Codeigniter, Yii, RESTful API, JSON, XML, Payment Integrations, HTML, CSS, and Jquery wit Lebih banyak

$25 AUD dalam 1 hari
(11 Ulasan)
3.6
armanmohammad

i can do it for you. i am ethical hacker and penetration tester. if you interested then we can discuss in detail.i can start this job right now.

$25 AUD dalam 1 hari
(0 Ulasan)
0.0
Miteshbhaip

I'm new with freelancer but I have 2+ year experience working with it, I have done a similar type of project in the past. DM me if you want to work with me.

$10 AUD dalam 3 hari
(0 Ulasan)
0.0
zurso

please describe your scripts operation I have good experience in PHP and MySql then i will find your scripts bugs

$30 AUD dalam 1 hari
(0 Ulasan)
0.0
kamelkimo1

hi bro I read what you want and I think that I can help you just leave a message or tell me I just need a munites for see if you are in the right way

$25 AUD dalam 1 hari
(0 Ulasan)
0.0